April
1999 QUESTION 5 Total Marks: 20 Marks |
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questions
GRADE A
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(a) | (i) How many functions are there from a set with three elements to a set with four elements? Explain your answer. | [2] |
(ii) How many functions are there from a set with four elements to a set with three elements? Explain your answer. | [2] | |
(i) The 1st element
can map to one of the elements in 2nd group. The 2nd element can also map to one of the elements in 2nd group (as the 2nd element can have same range as the 1st element). Same for the 3rd element. \ no. of functions = 4 * 4 * 4 = 64 (ii) The 1st
element have a selection of 3 elements in 2nd group, so as the 2nd, 3rd, and 4th elements.
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(b) | (i) How many one-to-one functions are there from a set with three elements to a set with four elements? Explain your answer. | [2] |
(ii) How many one-to-one functions are there from a set with four elements to a set with three elements? Explain your answer. | [2] | |
(i) The 1st element
has a selection of 4 elements. The 2nd element has a selection of 3 elements. The 3rd element has a selection of 2 elements. \ no. of one-to-one functions = 4 * 3 * 2 = 24
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(c) | (i) How many onto functions are there from a set with three elements to a set with four elements? Explain your answer. | [2] |
(ii) How many onto functions are there from a set with four elements to a set with three elements? Explain your answer. | [2] | |
(i) No onto functions
as the number of elements in the first group is less than the numbers of elements in the
2nd group. (ii) (3 *
1 * 2 * 1) + (3 * 2 * 2 * 1) + (3 * 2 * 1* 3) = 6 + 12 + 18 = 36
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(d) | (i) How many invertible functions are there from a set with three elements to a set with four elements? | [1] |
(ii) How many invertible functions are there from a set with four elements to a set with three elements? | [1] | |
(i) No invertible
functions. In order to have invertible functions, it must be one-to-one and onto. In this
case, since the number of elements in the 1st group is less the 2nd group. It is no onto
function and therefore no invertible functions. (ii) No invertible functions. As it has no one-to-one function (refer to b(ii)), therefore no invertible functions.
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(e) | Construct a function from three elements to two elements which is neither one-to-one nor onto. | [2] |
All three elements in
the domain must map onto one element in the range.
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(f) | The relation R, "is a factor of
" is defined on ![]() |
[4] |
R is reflexive as
every number is a factor of itself. R is not symmetric as 3 is a factor of 6 but 6 is not a factor of 3. R is transitive as if a is a factor of b, and b is a factor of c, then a must also be a factor of c. |