August 1999
MA214 : DISCRETE MATHEMATICS

QUESTION 4

Total Marks: 20 Marks'

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Question 4

(a) Define the function f : Z ® Z by the rule

f (n) = 2n, for all integers n.

(i) What property must be true of a one-to-one function?

(ii) What property must be true of an onto function?

(iii) Is f one-to-one? Prove or give a counter example.

(iv) If f onto? Prove or give a counter example.

 

 

 

[1]

[1]

[2]

[2]

(i)
A function g : A
® B is one to one if
         
"x, y Î A, g(x) = g(y) implies x = y

 

(ii)
A function g : A
®
B is onto if
         for each y
Î B, 
$x Î A such that g(x) = y

 

(iii)
f is one to one. One mark

        f (n) =  f(m)
              
Û   2 n = 2m      [definition of f ]
              
Û   n = m           [arithmetic]

 

(iv)
f is not onto. One mark
No element maps onto 1 (or indeed any of the odd numbers).
(b) Let S be the set {a,b}, and define S4 to be the set of all strings over  of length 4.
(i) List all sixteen elements of S4.

The relation R is defined on S4 as follows:

for all s, t Î S4, s Rt Û s has the same first two characters as t.

(ii) Is aabb R aabb?

(iii) Is abba R baab?

(iv) Write down all the elements which are related to abba.

 

[3]

 

 

[1]

[1]

[2]

(i)

      pic11.gif (4931 bytes)

 

(ii)
Yes

 

(iii)
No

 

(iv)
abaa, abab, abba, abbb

 

(c) (i) What properties must be an equivalence relation hold?

(ii) D is the binary relation defined on R as follows:

" x,y Î R, xDy Û xy ³ 0

Is D an equivalence relation? Justify your answer.

 

[4]

 

 

[3]

(i) A relation R : S « S is
  • reflexive if
               for each a
    Î S, (a, a) Î R
    one mark.
  • symmetric if
               for each a, b
    Î S, if (a, b) Î R then (b, a) Î R
    one mark
  • transitive if
               for each a, b, c
    Î S, if (a, b) Î R and (b, c) Î R then (a, c) Î R
    one mark

A relation is an equivalence if it it reflexive, symmetric and transitive.

 

(ii)
D is not an equivalence relation since it is not transitive:
          (1, 0)
Î D since 1 x 0 = 0 and 0 ³
0 and
         (0, -1)
Î D since 0 x -1 = 0 and 0 ³ 0 but
        (1, -1)
Ï
D since 1 x -1 = -1 and -1 < 0